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Matlab ( True or False questions
)
Statement while - end does not need a "conditional...
C Programming Can someone please explain me while the following (c) code prints out 6? for...
C Programming Can someone please explain me while the following (c) code prints out 6? for (i=1; x<=5; i++); printf ("%d",i); i=1 initializes the the loop, it is being tested whether it is <= 5 or not. This statement is true, so it goes into the loop and prints 1. After that, i++, means 1+1=2, i=2. This statement is being tested and it is true, we go into the loop and print 2. Then i=3, true, loop prints 3 -->...
#include <stdio.h> #include <sys/time.h> #define DEBUG 1 //Constant is defined for true int main() { struct timeval start,end; //to store time of starting and ending of program //if state...
#include <stdio.h>
#include <sys/time.h>
#define DEBUG 1 //Constant is defined for true
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
//if statement is added
if(DEBUG){
gettimeofday(&start,0);
}
printf("Time in microsecond for every second: \n"); //output
for(int i=0;i<100;i++) //outer loop to run 100 times
{
struct timeval loopstart,loopend; //to store time of starting
and ending of loop
//if statement added
if(DEBUG){
gettimeofday(&loopstart,0); //measuring time at start of
loop
}
for(int j=0;j<1000000;j++); //outer loop to...
need help adjusting my while loop to avoid this error, this is in matlab 1 clear...
need help adjusting my while
loop to avoid this error, this is in matlab
1 clear all close all 2 3 4 5 6 Egivens EO = 3; Sinput voltage ls = 7*10^-14; Svalue of ls R = 200; $value of resistor C = .026; $value of KT/ 7 8 9 10- V_vec = []; 11 vdiode (1) = 1; $initial guess for Vdiode 12 i=1; 13 14 %iterate until difference between last 2 Vdiodes < 10^-6 15 - while...
2. What is the output of the following code fragment? n = 1; while (n <=...
2. What is the output of the following code fragment? n = 1; while (n <= 5) { n++; cout << n << ' '; a.1 2 3 4 5 b. 1 2 3 4 c. 1 1 1 forever d. 2 3 4 5 e. 2 3 4 5 6 3. What is the termination condition for the following While loop? while (beta > 0 && beta < 10) { cout << beta << endl; cin >> beta; }...
QUESTION 1 Which statement results in the value false? The value of count is 0; limit...
QUESTION 1 Which statement results in the value false? The value of count is 0; limit is 10. (count != 0)&&(limit < 20) (count == 0)&&(limit < 20) (count != 0)||(limit < 20) (count == 0)&&(limit < 20) 10 points QUESTION 2 If this code fragment were executed in an otherwise correct and complete program, what would the output be? int a = 3, b = 2, c = 5 if (a > b) a = 4; if (...
(use only variables, expression, conditional statement and loop of c programming) ***C programming** int sum_of_cubes(int n)...
(use only variables, expression, conditional statement and loop
of c programming)
***C programming**
int sum_of_cubes(int n) {
}
int quadrant(int x, int y) {
}
int num_occurrences_of_digit(long num, int digit) {
return 0;
}
3.1 int sum_of_cubes(int n) This function should return the sum of the cubes of the first n integers. For example, if n is 4, it should return 13 +23+ 39 +4°. There is a simple formula for the result: 3x = ((n + 1)) = +...
task1 code： #include <stdio.h> #include <sys/time.h> int main() { struct timeval start,end; //to store time of starting and ending of program gettimeofday(&start,0); printf("Time...
task1 code：
#include <stdio.h>
#include <sys/time.h>
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
gettimeofday(&start,0);
printf("Time in microsecond for every second: \n"); //output
for(int i=0;i<100;i++) //outer loop to run 100 times
{
struct timeval loopstart,loopend; //to store time of starting
and ending of loop
gettimeofday(&loopstart,0); //measuring time at start of
loop
for(int j=0;j<1000000;j++); //outer loop to run 1000000
times
gettimeofday(&loopend,0); //measuring time at end of
loop
//calculating time for one iteration
long ms=(loopend.tv_sec-loopstart.tv_sec)*1000000...
True or false 27. Java compiler does not ignore white spaces such as spaces, tabs, or...
True or false 27. Java compiler does not ignore white spaces such as spaces, tabs, or blank lines in a Java program. 28. The same variable name(s) can be declared and used within different methods. 29. In Java, 3*'b'+1 is a valid expression. 30. In Java x++ is equivalent to x=x+1. 31. In Java, int x-2.5; is a valid statement. 32. The data type of the Java expression (int) 2.5 is double. 33. A method in Java can return more...
MATLAB ONLY!! PLEASE WRITE IN COMPUTER SO I CAN COPY PASTE!!! ANSWER COMPLETELY, USE FOR LOOPS....
MATLAB ONLY!! PLEASE WRITE IN COMPUTER SO I CAN COPY
PASTE!!! ANSWER COMPLETELY, USE FOR LOOPS.
THE PROGRAM TO BE MODIFIED IS THE NEXT ONE:
clc
clear
% Approximate the value of e ^ x using the Taylor Series
x = input( 'Enter the value of x for e^x. x = ' );
t = input( 'Enter the amount of desired terms. t = ' );
i = 1;
e_taylor = 0; % initializing the variable for the
accumulator
while...
The ability of computers to perform complex tasks is built on combining simple commands into control...
The ability of computers to perform complex tasks is built on combining simple commands into control structures. Of these control structures, blocks, while loop, the do..while loop, and the for loop. A block is the simplest type of structured statement. Its purpose is simply to group a sequence of statements into a single statement. The format of a block is: { } Here are two examples of blocks: { System.out.print("The answer is "); System.out.println(ans); } // This block exchanges the...
#include <stdio.h>
#include <sys/time.h>
#define DEBUG 1 //Constant is defined for true
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
//if statement is added
if(DEBUG){
gettimeofday(&start,0);
}
printf("Time in microsecond for every second: \n"); //output
for(int i=0;i<100;i++) //outer loop to run 100 times
{
struct timeval loopstart,loopend; //to store time of starting
and ending of loop
//if statement added
if(DEBUG){
gettimeofday(&loopstart,0); //measuring time at start of
loop
}
for(int j=0;j<1000000;j++); //outer loop to...
need help adjusting my while
loop to avoid this error, this is in matlab
1 clear all close all 2 3 4 5 6 Egivens EO = 3; Sinput voltage ls = 7*10^-14; Svalue of ls R = 200; $value of resistor C = .026; $value of KT/ 7 8 9 10- V_vec = []; 11 vdiode (1) = 1; $initial guess for Vdiode 12 i=1; 13 14 %iterate until difference between last 2 Vdiodes < 10^-6 15 - while...
(use only variables, expression, conditional statement and loop
of c programming)
***C programming**
int sum_of_cubes(int n) {
}
int quadrant(int x, int y) {
}
int num_occurrences_of_digit(long num, int digit) {
return 0;
}
3.1 int sum_of_cubes(int n) This function should return the sum of the cubes of the first n integers. For example, if n is 4, it should return 13 +23+ 39 +4°. There is a simple formula for the result: 3x = ((n + 1)) = +...
task1 code：
#include <stdio.h>
#include <sys/time.h>
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
gettimeofday(&start,0);
printf("Time in microsecond for every second: \n"); //output
for(int i=0;i<100;i++) //outer loop to run 100 times
{
struct timeval loopstart,loopend; //to store time of starting
and ending of loop
gettimeofday(&loopstart,0); //measuring time at start of
loop
for(int j=0;j<1000000;j++); //outer loop to run 1000000
times
gettimeofday(&loopend,0); //measuring time at end of
loop
//calculating time for one iteration
long ms=(loopend.tv_sec-loopstart.tv_sec)*1000000...
True or false 27. Java compiler does not ignore white spaces such as spaces, tabs, or blank lines in a Java program. 28. The same variable name(s) can be declared and used within different methods. 29. In Java, 3*'b'+1 is a valid expression. 30. In Java x++ is equivalent to x=x+1. 31. In Java, int x-2.5; is a valid statement. 32. The data type of the Java expression (int) 2.5 is double. 33. A method in Java can return more...
MATLAB ONLY!! PLEASE WRITE IN COMPUTER SO I CAN COPY
PASTE!!! ANSWER COMPLETELY, USE FOR LOOPS.
THE PROGRAM TO BE MODIFIED IS THE NEXT ONE:
clc
clear
% Approximate the value of e ^ x using the Taylor Series
x = input( 'Enter the value of x for e^x. x = ' );
t = input( 'Enter the amount of desired terms. t = ' );
i = 1;
e_taylor = 0; % initializing the variable for the
accumulator
while...
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