Question

Knowing that at the instant shown the angular velocity of rod DE is 2.7 rad/s clockwise, determine the velocity of collar A and the velocity of point B. 80 mm 150 mm TO 60 mm 120 mm The velocity of collar A is The velocity of point B is mm/s. mm/s À 61.8º.

Answer 1

Solutions given Woe 2 2 4 radise sloutу tо ) : Tv. . . oъс Voz 288 mmis CM where VoE = 120mm » I voz 288 mmin ] Now, to would be caulting along y direction . huu 1, 2 и 3 mm 4 | we know from figure Thin - pommit 180 mm) Now, we will calculate Jain & woor VAM = (WADÊ Î [c1s0mm) ? (80mm)?] = 80 WA Î - 150 WADA @ . Now velocity at 6 given as JA = VD e VALA we know I would act along +x-direction so JAZ VAI WARE (288 mnio) i 150 waste 80 WADI . Calong x-asia) (along y-aris) lui a NA = - WAD 150 and 0=288 mils +8wAD =-3.6 radla placing, wan NA a-(-3:6) iso TVA a 440mmia

I NA Vw Now we will calulate tuo = Joe uBiolo we already have Jo., letă calealate VBIA from diagram for rol ADA MALA? Vaio X (60 mm) = -0.4.CMD -0.4 1.80mm îę (somm] , roro - - 32 – 60° - Isomm) Now , PiBIA = GRADEN BID (-3.6 Â) x ( -32Ť - 601) - 22617 + 115-25 from 0 wom 3885 - 218 î + 115.25 J = (-216 7 + 4 03.2 7 ) mmin lumia 56-21624 (403.2) 2 Tivela 457mmin at 649" os tan " ( ?).tamaki - 161.80] Please do up rode!!!) 1m -21

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