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A charge of -0.30 C is placed on a circular conducting plate (very thin) with radius R= 10 cm. a) Draw a diagram of the situa

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The surface charge density is: = Q πα -0.30 A(0.10) = -9.5 C/m2 2 a b) The electric field at the given distance is:N 1 - E= 260 VpP+R? 0.03 1 - -9.5 2(8.85x10-12) = -3.8×10IN/ 0.03 +0.107 c)The electric field at the given distance is: N .X

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