Question

For the following reaction:

NiO₂(s) + 4 H⁺(aq) + 2 Ag(s) → Ni²⁺(aq) + 2 H₂O(l) + 2 Ag⁺(aq)    ℰ^° = 2.48 V

Calculate the pH of the solution if ℰ = 2.39 V and [Ag⁺] = [Ni²⁺] = 0.029 M. (See this table.)

Answer 1

For the following reaction! NIO, (5) + 4H*(09) + 219 (3) —— Nilteaq) + 2 H2060) + zag trag) E = 2.48V Calculate the pH of the solution if E= 2.39v. and [agt] = [Ni 2+] = 0.029M. The reaction is Mio (3) + 4H+ car) + 2 Ag (8) Ninfas) + 2H20(e) Quron, 7-2.48V. E =-2.39V. + 2Agtcar. [Agt] = {Ni 2+] = 0.029 M. According to Nernst equations we can write- E = E° - 0.059 log I Ni2+] [49132 2 0 644+14 on, 2139 = 2:48 – 0-05.910g (wit] [ag 132-0.059 boy 4 or; 2139 = 2:48 – 0.0590g (0-029) (0.029) + 0.059109 CH+24 OF, 2.39 = 2048 - (-0.1360) – 0-05984 (-ky CH 13) or 2.39 = 2.48 +0.1360 -0.059x) pH. or, 239 = 20616 – 0.118 PH or, 0.118 PM = (2616-239). o pH = 0.226 0.118 PM -1.915 2 Anwer, the pH of the solution is 1.915.