Homework Answers
Solution
49)
Total storage capacity
= 6*500=3000 GB
RAID 0
6*500
=3000 GB
RAID 1
(6/2) *500
=1500 GB
RAID 3
(6-1)* 500
=2500 GB
RAID 4
(6-1)*500
=2500 GB
RAID 5
(6-1)*500
=2500 GB
RAID 6
(6-2)*500
=2000 GB
How does the OS interact with each of the six drives in the array?
RAID 0
RAID 0 has striping but there is no redundancy
RAID 0 offers the best performance but no fault tolerance
RAID 1
RAID1 also known as disk mirroring
RAID 1 contains at least 2 drives that duplicate the storage of data
RAID 1 has no striping
Performance of read can be improved because either disk can be read at the same time
RAID 2
RAID 2 has striping across disks
RAID 2 storing error checking and correcting information
RAID 3
RAID 3 uses striping and completely dedicates one drive to storing parity information
Data recovery in RAID 3 is done by XOR of the information recorded on the other devices
RAID3 is mainly used for single user systems with long record applications
RAID 4
RAID 4 uses large stripes it means you can read records from any drive
It allows to use overlapped Input/Output for read operation
RAID 5
RAID 5 based on block level striping with parity
The information of parity is striped across each drive
It allow the array to function even it fails
The architecture of array allow read & write operations to span multiple drve
The performance of RAID 5 is usually better than single drive
RAID 6
RAID 6 is similar to RAID 5
It includes second parity scheme that is distributed across the drives in the array
Additional parity will allow the array to continue to function even if 2 disks fail simultaneously
RAID 6 arrays have a higher cost per GB and slower write performance then RAID 5 arrays
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