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Constants PartA A coil has a resistance of 46.0 Ω . At a frequency of 90.0 Hz the voltage across the coil leads the current in it by 52.2o Determine the inductance of the coil 1-1-0.2 138-0.2138 Submit Pre vious Answer s Regquest Answer Incorrect; Try Again; 3 attempts remaining

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Answer #1

According to the given problem,

Using the concep tog ressitance in RL circut,

XL = 2 π f L----(1)

XL = Rtanθ----(2)

From eq 1 and 2,

L = R*tanθ/ 2 . π . f

= 46*tan52.2o / [2π *90]

= 0.104870H

= 0.105 H

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