Question

Ql. The following MATLAB code computes the cosine value ranging from 0 to 10 using vectorization technique: t = 0:1:10; y cos (t); Rewrite the code above using i. for loop ii. while loop (5 marks)

Answer 1

Given code:

clc;
clear;

t=0:1:10;
y = cos(t);
y

clc; clear; 1 2 3 4 5 6 7 t=0:1:10; Y = cos(t); Y

output:

y = 1.00000 0.54030 -0.41615 -0.98999 -0.65364 0.28366 0.96017 0.75390 -0.14550 -0.91113 -0.83907

Using for loop:

clc;
clear;

y = []; %empty vector to store cosine values.
for t=1:11 %it will run 1 to 11 so run 11 times.
y(t) = cos(t-1); %calculating consine values 0 to 10 and strong in vector.
endfor
%printing the cosine values.
disp("Using for loop: ")
y

1 clc; 2 clear; 3 4 y = []; $empty vector to store cosine values. 5 for t=1:11 fit will run 1 to 11 so run 11 times. 6 y(t) cos (t-1); fcalculating cosine value o to 10 and storinng in vector. 7 Lendfor 8 sprinting the consine values. 9 disp ("Using for loop: ") 10 y

output:

Using for loop: y = 1.00000 0.54030 -0.41615 -0.98999 -0.65364 0.28366 0.96017 0.75390 -0.14550 -0.91113 -0.83907

Using while loop:

clc;
clear;

y = []; %empty vector to store cosine values.
t=1; %staring with 1 because vector index starts with 1.
while t<=11 %up to 11 ie. it will run 11 times.
y(t) = cos(t-1); %calculating cosine value 0 to 10 and storinng in vector.
t += 1; %increaseing the t value.
endwhile
%printing the consine values.
disp("Using while loop: ")
y

1 clc; 2 clear; 3 4 y = []; tempty vector to store cosine values. 5 t=1; $staring with 1 because vector index starts with 1. 6 Ş]while t<=11 fup to 11 ie. it will run 1 times. 7 y(t) cos (t-1); calculating cosine value 0 to 10 and storinng in vector. 8 t += 1; Sincreaseing the t value. 9 Lendwhile 10 Sprinting the consine values. 11 disp ("Using while loop: ") 12 Y

output:

Using while loop: y = 1.00000 0.54030 -0.41615 -0.98999 -0.65364 0.28366 0.96017 0.75390 -0.14550 -0.91113 -0.83907

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