Question

In the given figure, the horizontal axis is the elapsed time with each box as 0.5 second. First, assume that the vertical axis is the displacement x with each box representing 0.25 meters.

a) Figure out the displacement magnitude of instantaneous velocity at point B.

b)In which region(s), if any does the object have negative Vx? Why?

c) Calculate the average velocity Vx between points D and F.

Now, assume that the vertical axis shows the velocity V_x, with each box representing 0.5 m\s

d) In which region(s), if any, does the object have a non-constant acceleration a_x? Why?

e) Calculate the average acceleration a_x between points C and E.

Answer 1

given,

horizontal axis is the elapsed time with each box as 0.5 second

vertical axis is the displacement x with each box representing 0.25 meters

displacement magnitude of instantaneous velocity at point B = 0.25 + 0.25

displacement magnitude of instantaneous velocity at point B = 0.5 m

region E to F has negative Vx since the slope of the graph is negative in this region and slope of the displacement-time gives the velocity

average velocity = total distance covered / total time taken

total distance covered between point D and F = (9 - 4) * 0.25

total distance covered between point D and F = 1.25 m

total time between D and F = 5 * 0.5

total time between D and F = 2.5 sec

average velocity = 1.25 / 2.5

average velocity = 0.5 m/s

in region A to D the object will have non constant acceleration as slope of the graph will give the acceleration and in this region slope is not constant