Question

ENGT 312 Intro to Applied Statics: Module 1 Test Spring 2020 (A) Find the resultant force acting on the Hook Boltat point A. Give answer in Cartesian representation (pt) (B) Find the angle between the two Force Vectors (10pts) 2) F 750 TL 140 pt

Answer 1

In question we are asked to find out the resultant vector for two given forces and angle between them.

TA(0,0,4) 7501b B =60010 Hz Ty DAG IF B 4 34 (2,4,6) Fiert find position vectors of all points A, B and | Pv: o A = + + 4k P.V. of B = 39 - 3ỳ +2.5k pv. of c = ah+uj tok AB = P.N. of B - P. V. of A AB = 3î - 3] - I.S (3,-3,2.5) AC = ai tuj-48 68 = tế - ( 33 - 35 -1.5k) . ! * hac a main = $(29+uj =4R) Now fance FB in direction of A² Fe = lſol AB = 600 (34–39–1.5k) % = 133.34 (31-31 -1.58 ) = too – noi - 200k similarly fe in diection of Âc F = I FI AC = 125 (20+49-4Â) = 250 î + 5009 – 500 Â Resueltant fonce using triangle law FR = Fot Fe = 2009–400)-200 +250 +5009-sook FR = 650 î + 1009- 700 h I FRI = 960.468616 For Cartesion cepresentation direction of resultant given by ) d = cast 60% Ge1 = cost 609960.4686 = 53°20'-24 B = cost 10% fel = 848168 ra castro y = 136.78 27

Now pout (B) angle between the two fonce vector Cases Foo Fe 4002_40o9-2ook),(ascũ + sooj-sook) 600 x 750 coba = 0 =>0=900]