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n=last two digit of your id m=0.7*n Problem 1 For the circuit shown below . ______[20] ---------------------- m+1 92 m+42 m+4

n=32

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ginen , n=32 m. 0.1x n = 0. 1x 3.2 m= 3.2 for t=0, nj and suct are active sources. and the circuit is in steady state befoll110) = 32 - 4.2 i, – 32- 4.2x 2.807 - 20-21 v AS Inductor does not allow sudden change in clonent and capacitor does not alloApplying nodal analysis, at v v- e . + llo) + 2 = 0 7.2 [ 2 + 2 + 1 - 2 3 - ve + 3.50 1 = 0 7.2 At HVE * -C0249 + Bolu = 3.58von = 1 = 3.501) – (0.277 + 0.51 10+ 5-0825 -0.139 a = 10. 139 - (0.277 + 0.5 l 10- 377 +0.255 -0.139 = -(0-18 9) (0-138) + (

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