Homework Answers
a )
= xd/nL = ( 5 x
10^-2) (5.10 x 10^-5) / 3 (1.40)
= 6.07 x 10^ -7
m
b) distance between adjacent fringes= ( 6.07 x 10^ -7) (1.40 )/ (5.10 x 10^-5) = 1.67 x 10^-2 m
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