Question

Member CB has a square cross section of 30 mm on each side. (Figure 1) Part A Determine the largest intensity w of the uniform loading that can be applied to the frame without causing either the average normal stress or the average shear stress at section b-b to exceed o= 12 MPa and t= 16 MPa, respectively. Express your answer to three significant figures and include appropriate units. ? c': Å * * o a Value Units Figure < 1 of 1 > Submit Request Answer Provide Feedback Next > 4 m

Answer 1

Date 19|04|2020 Given That, Cooss Seccion member of CB - 30 mm The Average Normal Stress at Section bb (o)= 12 MP The average shear stress at Section bab lay = 16 mpa. Given the figure, Now Convert momber BA contel. udh to cunifovonly distributed Load) on point load as wxh acting at » ual to point Load = wxl = wrz >30 @ mid spars FBD fBesine By Rosolving, Free Kodeffe coso FBC 1.500 > 3039 130 1-571 నేను రుదుకుల విద్యాలయాల సంస వారి ఉచిత సరఫరా విత సరఫున

Now, we have to calculate o, so that, > O= tan' (4/3) fano = 4 0 = 53.13 = Take moment at A is zero CEMA=0) & . (ABC sino)x3 - (3wxlos) 3wxlos = 1-87500 3x SÅD (53.18%) Nowe, FRD fo Be member yfoc F Abe sino 1. b ř Noa Novosal vb= shear force free b b section section - No Nowe, Efeso, SO be sino arbat > vb= 1.875wx Sh 53.18² Nb=15w Semebrly, Efyzo, FBC Coso -Nb =0 1-87510 cos 53.13 -Nb=0 No=11250

Area of the member CB A = 30x30 » 9000m, a eu = 900X10 m2 i Area at soction bab (Abb) = A 2030 = quor166 COS 5330 = isooxio tome 30, mezimicos Meuomal stress at bab is, Ouba Qocasal force bb (Area) grb 12x66 = 10125w lobb= lampa 1500x66 =12x10 N/m2 Los 15toxl2 = 16000 Non 10125 us = 16 kuulos shear strees at bb is, maximuos Tob a vb A-bb 16X106 = 1050 1500xido 105 w - fresley istor1b = ltooonloos = 16knol.com Jaugest intensity can in uke 316 wedley