For the reaction H^2 (g) + S(s) right arrow H^2 (g), delta?degree = - 20.2 kJ/mol...
For the reaction H2(g) + S(s) --> H2S(g) delta H = -20.2 kJ mol-1 and delta S =+43.1 J K-1mol-1. Which of the following statements is true? The reaction is spontaneous at all temperatures. delta G becomes less favorable as T is raised. The reaction is only spontaneous at high temps. The reaction is only spontaneous at low temps. The reaction is at equilibrium at 25 C under standardconditions. Please explain why too. Thank you, feedback will beawarded as soon...
For the reaction N_2(g) + 3 H_2(g) rightarrow 2 NH_3(g) Delta G degree = -23.6 kJ and Delta S degree = -198.7 J/K at 345 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 345 K. The standard enthalpy change for the reaction of 2.30 moles of N_2(g) at this temperature would be kJ. For the reaction 2 H_2O_2(l) rightarrow 2 H_2O(l) + O_2(g) Delta G degree = -236.9 kJ and Delta H degree =...
A certain reaction has Delta H degree = -22.50 kJ and Delta S degree = -75.50 J/K. Is this reaction exothermic, endothermic or isothermic (neither)? This reaction is Does this reaction lead to a decrease, an increase, or no change in the degree of disorder in the system? This reaction leads to in the disorder of the system. Calculate Delta G degree for this reaction at 298 K. If this value is less than 1 kJ/mol then enter 0 in...
Use deltaH and S to calculate DeltaG rxn...
Use Delta H degree_f and S degree to calculate Delta G degree rxn (Delta G degree sys) at 25 C for the reaction below: 4 KClO3 (s) rightarrow 3 KClO4 (s) + KCl (s) Delta H degree_f KClO3 = -397.7 kJ/mol; KClO4 = -432.8 kJ/mol; KCl = -436.7 kJ/mol S degree KClO3 = 143.1 kJ/mol; KClO4 = 151.0 kJ/mol; KCl = 82.6 kJ/mol
For a given reaction, Delta H = -19.9 kJ/mol and Delta S = -55.5 J/K-mol. Calculate the temperature in K where Delta G = 0. Assume that Delta H and Delta S do not vary with temperature. Also, what is the equilibrium constant at that temperature?
Using the values of Delta H and Delta S given, calculate Delta G for each of the reactions at 25 degree C and indicate whether the reactions are spontaneous or non-spontaneous. Explain. Delta H = 10.5 kJ/mol and Delta S = 30.0 J/K-mol Delta H = -10.5 kJ/mol and Delta S = 105. J/K-mol
8.) From the values of delta H and delta S, calculate delta G then predict whether the following reactions would be spontaneous or not at 25 C. a) Reaction A: delta H= 10.5 kJ/mol, and delta S = 30 J/K mol b) Reaction B: delta H=1.8 kJ/mol, and delta S = -113 J/K mol 9.) Calculate the delta G and K, for the following equilibrium reaction at 25 C: 2H2O(Ⓡ) <-> 2H2(g) + O2(8) delta Gran H2O(x) = -228.6 kJ/mol
DeltaH degree is +23 kJ mol^-1 of phosphine (PH_3) for the reaction Calculate Delta S degree for this reaction. Explain how this information allows you to determine the spontaneity or non-spontaneity of this reaction at any temperature. (S degree for PH_3 is 210 J K^-1 mol^-1.) Do these results indicate anything about the possibility of the existence of phosphine? Explain your answer.
a reaction has delta H = 100.0 kJ/mol and delta S = 250.0 J/mol K. Is the reaction spontaneous at room temperature? If no, at what temperature (in K and C) does this reaction become spontaneous?
Consider the reaction N2H4(l)_ 3O2(g)---> 2NO2(g) +2H2O(l). Data: DeltaGof formation(kJ/mol) for N2H4(l)=149.2, S (J/Kmol) for N2H4(1)= 121.2 calculate the following at 25C. (I) DeltaS of rxn (J/Kmol) (II) delta H of rxn (kJ/mol) (III) Delta G of rxn (kJ/mol) from the results of (I) and (II) (IV) delta G of reaction (kJ/mol) from DeltaG of formation data (V) are the results of (III) and (IV) expected to be the same? Explain - Calculate the Delta G for the reaction in...