Consider the reaction N2H4(l)_ 3O2(g)---> 2NO2(g) +2H2O(l). Data: DeltaGof formation(kJ/mol) for N2H4(l)=149.2, S (J/Kmol) for N2H4(1)=...
Consider the reaction N2H4(l)_ 3O2(g)---> 2NO2(g) +2H2O(l).
Data: DeltaGof formation(kJ/mol) for N2H4(l)=149.2, S (J/Kmol) for N2H4(1)= 121.2 calculate the following at 25C.
(I) DeltaS of rxn (J/Kmol) (II) delta H of rxn (kJ/mol) (III) Delta G of rxn (kJ/mol) from the results of (I) and (II) (IV) delta G of reaction (kJ/mol) from DeltaG of formation data (V) are the results of (III) and (IV) expected to be the same? Explain
- Calculate the Delta G for the reaction in problem III when Po2=0.0775 arm, Pno2= 6.00x10^-3 atm.
Data: Delta G of formation for N2H4 is +110.5. O2 is 0. NO2 is +51.3. H2O is -237.1.
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Consider the reaction N2H4(l)_ 3O2(g)---> 2NO2(g)
+2H2O(l).
Data: DeltaGof formation(kJ/mol) for N2H4(l)=149.2, S (J/Kmol)
for N2H4(1)=...
1. For the reaction: N2(g) + O2(g)=2NO(g), deltaH° = 181 kJ and deltaS° = 24.9 J/K,...
1. For the reaction: N2(g) + O2(g)=2NO(g), deltaH° = 181 kJ and deltaS° = 24.9 J/K, deltaG° would be negative at temperatures (above, below) ?????K. Enter above or below in the first box and enter the temperature in the second box. Assume that deltaH° and deltaS° are constant. 2. For the reaction: 2BrF3(g)=Br2(g) + 3F2(g), deltaH° = 542 kJ and deltaS° = 269 J/K, G° would be negative at temperatures (above, below) K. Enter above or below in the first box...
Determine delta H^0 for the reaction: N2H4(l) + O2(g) -----> N2(g) + 4H2O(l) From these data:...
Determine delta H^0 for the reaction: N2H4(l) + O2(g) -----> N2(g) + 4H2O(l) From these data: N2H4(l) + 2H2O2(l) ----> N2(g) + 2H2O(l) delta H^0 = -622.2 KJ H2(g) + 1/2 O2(g) ----> H2O(l) delta H^0= -285.5KJ H2(g) + O2(g) -----> H2O2(l) delta H^0= -187.8KJ
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data...
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
For the reaction H^2 (g) + S(s) right arrow H^2 (g), delta?degree = - 20.2 kJ/mol...
For the reaction H^2 (g) + S(s) right arrow H^2 (g), delta?degree = - 20.2 kJ/mol and deltaSdegree = + 43.1 J/K-mol. Calculate deltaGdegree at 500degreeC. For the reaction H^2 (g) + S(s) right arrow H^2S(g), delta?degree = - 20.2 kJ/mol and deltaSdegree = + 43.1 J/K mol. Use the deltaGdegree value calculated at 500degreeC. Calculate deltaG for this reaction at 1500degreeC if P(H^2, g) = P(H^2S, g) = 10.0 atm. Show all standard calculation.
1. Hydrazine is used to remove dissolved oxygen from the water in water heating systems. N2H4(l) + O2(g) à 2H2O(l) + N2(g) What is the free energy changed observed when 1.00...
1. Hydrazine is used to remove dissolved oxygen from the water in water heating systems. N2H4(l) + O2(g) à 2H2O(l) + N2(g) What is the free energy changed observed when 1.00 mole of N2H4 is oxidized? (for hydrazine ∆G°f = 149.2 kJ/mol) What is the free energy change for the oxidation of 1.00 pound (454 g) of hydrazine? 2. Calculate the standard free energy change and equilibrium constant for the following reaction at 25 °C. 4Ag(aq) + O2(g) + 4H+(aq)...
Nitrogen Ahºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 191.6 N2(9) 0 0 N(g) 472.7 455.6 153.3 NH3(g) -46.1 -16.5 192.5 NH3(a...
Nitrogen Ahºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 191.6 N2(9) 0 0 N(g) 472.7 455.6 153.3 NH3(g) -46.1 -16.5 192.5 NH3(aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 90.3 86.6 210.8 NO(9) NOCI(g) 51.7 66.1 261.8 NO2(g) 33.2 51.3 240.1 N20(9) 82.1 104.2 219.9 N204(9) 9.2 97.9 304.3 N204(0) -20.0 97.0 209.0 N205(s) -42.0 134.0 178.0 N2H4(0) 50.6 149.3 121.2 N2H3CH3 () 54.0 180.0 166.0 HNO3(aq) -207.4 -111.3 146.4 HNO3(1) -174.1 -80.7 155.6 HNO3(9) -135.1 -74.7 266.4 NH4ClO4(s) -295.0...
1. 1) luciferin+O2 ⇌ oxyluciferin+light 2) ATP⇌AMP+PPi ΔG∘=−31.6 kJ/mol If the overall ΔG∘ of the coupled...
1. 1) luciferin+O2 ⇌ oxyluciferin+light 2) ATP⇌AMP+PPi ΔG∘=−31.6 kJ/mol If the overall ΔG∘ of the coupled reaction is -1.21 kJ/mol , what is the equilibrium constant, K, of the first reaction at 11∘C? Round your answer to 3 significant figures. 2. When methanol (CH3OH) is combusted, such as when in a gasoline blend, the following reaction occurs: 2CH3OH(l)+3O2(g)→2CO2(g)+4H2O(g) Based on the standard free energies of formation given, what is the standard free energy change for this reaction? Report the answer...
Using the data: C2H4(g), = +51.9 kJ mol-1, S° = 219.8 J mol-1 K-1 CO2(g), = ‑394 kJ...
Using the data: C2H4(g), = +51.9 kJ mol-1, S° = 219.8 J mol-1 K-1 CO2(g), = ‑394 kJ mol-1, S° = 213.6 J mol-1 K-1 H2O(l), = ‑286.0 kJ mol-1, S° = 69.96 J mol-1 K-1 O2(g), = 0.00 kJ mol-1, S° = 205 J mol-1 K-1 calculate the maximum amount of work that can be obtained, at 25.0 °C, from the process: C2H4(g) + 3 O2(g) → 2 CO2(g) + 2 H2O(l)
For the following reaction: 2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(l) Compound ΔH°f (kJ mol-1)...
For the following reaction: 2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(l) Compound ΔH°f (kJ mol-1) S° (J mol-1 K-1) CH3OH (l) -238.40 127.19 O2 (g) 0.00 205.70 CO2 (g) -393.51 213.74 H2O (l) -285.83 69.91 Determine the temperature (to two decimal places in K) such that the reaction is in equilibrium in its standard states.
For the following reaction: 2Na(s) + 2H2O(l) → 2NaOH(s) + H2(g) Compound ΔH°f (kJ mol-1) S°...
For the following reaction: 2Na(s) + 2H2O(l) → 2NaOH(s) + H2(g) Compound ΔH°f (kJ mol-1) S° (J mol-1 K-1) Na (s) 0.00 51.30 H2O (l) -285.83 69.91 NaOH (s) -425.93 64.46 H2 (g) 0.00 130.68 Calculate ΔG°rx (in kJ) at 391.96 K for this reaction. Assume ΔH°f and S° do not vary as a function of temperature.
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
For the reaction H^2 (g) + S(s) right arrow H^2 (g), delta?degree = - 20.2 kJ/mol and deltaSdegree = + 43.1 J/K-mol. Calculate deltaGdegree at 500degreeC. For the reaction H^2 (g) + S(s) right arrow H^2S(g), delta?degree = - 20.2 kJ/mol and deltaSdegree = + 43.1 J/K mol. Use the deltaGdegree value calculated at 500degreeC. Calculate deltaG for this reaction at 1500degreeC if P(H^2, g) = P(H^2S, g) = 10.0 atm. Show all standard calculation.
Nitrogen Ahºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 191.6 N2(9) 0 0 N(g) 472.7 455.6 153.3 NH3(g) -46.1 -16.5 192.5 NH3(aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 90.3 86.6 210.8 NO(9) NOCI(g) 51.7 66.1 261.8 NO2(g) 33.2 51.3 240.1 N20(9) 82.1 104.2 219.9 N204(9) 9.2 97.9 304.3 N204(0) -20.0 97.0 209.0 N205(s) -42.0 134.0 178.0 N2H4(0) 50.6 149.3 121.2 N2H3CH3 () 54.0 180.0 166.0 HNO3(aq) -207.4 -111.3 146.4 HNO3(1) -174.1 -80.7 155.6 HNO3(9) -135.1 -74.7 266.4 NH4ClO4(s) -295.0...
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