Question

c++ language

TECH 1211 Computer Programming Name Test 2 Hands-On-Program B Spring 2020 Write a program that uses the quadratic formula to solve quadratic equations. Background Given the format for a quadratic equations: aX? +BX+C =0 The coefficient of the X term is the number a. The coefficient of the X term is the number b. The value of c is any non-zero constant. These values can be positive, negative or zero. You can find the solution to this equation by using the quadratic formula. That formula is as follows: X = -1b + V (b2-4ac) and X2 =-1b-V (b2-4ac means 'take the square root of 2a 2*a The expression, b-4 a' is called the discriminant and can be calculated. If the discriminant is a positive value there are 2 answers to the problem, X, and X. If the discriminant is a zero, there is only 1 answer to the problem called a repeated root. If the discriminant is negative, the answer to the problem is a complex number. Write a program that prompts the user to enter the values of a, b, and c for any quadratic equation. It then classifies the answer as a complex number, 2 different numbers, or a repeated root. It displays the answer to the problem using the correct format, (two numbers if the discriminant is positive, one number if the discriminant is zero and the phrase "Complex Number if the discriminant is zero. To square a value like b, type it into the program as: bºb To take the square root of the discriminant use the math function: sort/bºb-4*a*c) The output screen at the end of the session will look something like the following:

Answer 1

 #include <iostream> #include <cmath> using namespace std; int main() { float a, b, c, x1, x2, discriminant, realPart, imaginaryPart; cout << "Enter coefficients a, b and c: "; cin >> a >> b >> c; discriminant = b*b - 4*a*c; if (discriminant > 0) { x1 = (-b + sqrt(discriminant)) / (2*a); x2 = (-b - sqrt(discriminant)) / (2*a); cout << "Roots are real and different." << endl; cout << "x1 = " << x1 << endl; cout << "x2 = " << x2 << endl; } else if (discriminant == 0) { cout << "Roots are real and same." << endl; x1 = (-b + sqrt(discriminant)) / (2*a); cout << "x1 = x2 =" << x1 << endl; } else { realPart = -b/(2*a); imaginaryPart =sqrt(-discriminant)/(2*a); cout << "Roots are complex and different." << endl;