Question

5) Given the Determine following periodic waveforms (I) the average value of each (f) the rms value of each (opts) (sets) -+ -+ -+ ० -+- ॥ +--- 12 (mus) १ " T -..

Answer 1

8 . (6) Average value (Vang) from the above waveform Vm z 12-8 2 4 volts - fol full wave averge value Varg = 0 ( + peak and -th half wave average value Varg = 2vm - peak 2x4 . Varg = 2 volts] di) RM8 value :. Yoms = 2.828 Volts 7 -A-

(6) Average value of Triangular wave larg = um from the given waveform Vm = 7 volts Varg = 7 - Varg = 3.5 volts] () RM8 value of Triangulal wave Yomo = uma - :: Voms = 4.04 volto (0) to I ♡

. (6) Average value of square ware given – Given Squele lexuese showing that +8xolle fosh o to 1m duration and - 4 volts fh a to umsec. Then the Vang can be calculated as Vang = D x Vpx +(-D) * Vpka Wilhele Vore volts VPKY --4 Votte vity Duty cycle (D) - Hot Vaug = **+ (1 - 1w) x4 1 = 2 + 3x4 :: Vavg = 5 volts (11) RMB value of given square wave v - upit → If we opfume that the negative "Jupil part of the signal taken út a&io contribute in the delivery of power to the load of then the RMB value of up, and up to is given by. upp = va up = 16 Volti similarly upp = VP (Tuti)

2 (4-1) = 4*3 to y = 12 volts ". Total RMS value of given squake wave = Vans =

Vrms = 1 4/ 16+ 12 .. Vrms = 5.29 Vita + 2 į ý si Terma). " Average value of given pulse signal from the waveform given Vm = 15-5 = lo volte 1 Varg = Vm = 1 h Vaug = 7.071 volte (1) RMs value of given pulte ware Veems = yen = - 5 volt. Vemo = 5 volts]