Question

Suppose that the coefficient of friction between a car's tires and the road is 0.300 when the road is wet. If the car is going at 70.0 mph on a wet road and applies the maximum braking that does not result in a skid, what distance will it take for the car to stop? (Note: 1 mile = 1.609 km).

Answer 1

360o a ginen M=0.300 Initial velocity of the Car Vi=70 miles/howe = 10x Lb gols Vi = yoxlib. 90 Xlor min = 32.86mis Final velocity gao (stop condition ) using work energy wzor o work done by friction force wf = lngd - mr massa cor, dr distance travelled a Wg zol work done by granity) ok = Charge as kinetic energy of the car =kg-ki & £m (NA) ²- tmu? tim(o)²-timur putting value of wand BK an eq" ♡ wg twf = tmco²_tmut ó - limyo =0-mot de vida. (32.863€ [gicomise] Id=179.96 h 10om comment}. In this problem work done by the car is only against the friction force. No work is done against the gravitation because cs hondertical displacement, 2x0.300 x 10 CamScanner