Question

if it is possible help me with the code in C language and I could learn it, thanks !

Write a function that computes the integer mean of an array of integers. For example, the integer mean of -1, 4, 2 is (-1 + 4 + 2)/3 = 5/3 = 1, where/des integer division. The function should implement the following specification:/* Computes the integer mean of an array and stores it * where mn references. Returns -1 for erroneous input * (len <= 0 or NULL array); otherwise returns 0. int mean(int * a, int len, int * mn); Implement a unit test of mean in a main function.

Answer 1

Here is code:

int mean(int *a,int len,int *mn)
{
if(len <= 0 || a == NULL) // len is zero of a is null
{
return -1;
}
else
{
int sum = 0;
int i;
//calculate the sum of array
for(i = 0 ; i < len ; i++)
{
sum += *(a + i);
}
// calculate the mean
*mn = sum / len;
return 0;
}
}

Sample program to test:

#include <stdio.h>

int main()
{
int array[3] = {-1, 4, 2};
int *p;
p = array;
int var = 0; /* actual variable declaration */
int *m; /* pointer variable declaration */
m = &var; /* store address of var in pointer variable*/

int result = mean(p,3,m);
if(result == -1)
printf("Invlid input");
else
printf("result is %d\n",*m);

return 0;
}
int mean(int *a,int len,int *mn)
{
if(len <= 0 || a == NULL) // len is zero of a is null
{
return -1;
}
else
{
int sum = 0;
int i;
//calculate the sum of array
for(i = 0 ; i < len ; i++)
{
sum += *(a + i);
}
// calculate the mean
*mn = sum / len;
return 0;
}
}

Output:

result is 1