Question

java programming.

One. Write a method public boolean hasOnlyoddDigits(int n) that returns true if its parameter n contains only odd digits (1, 3, 5, 7, or 9), and returns false otherwise. Zero is counted as an even digit whenever it appears inside the number. Remember that for a positive integer n, the expression (n % 10) gives its last digit, and the expression (n / 10) gives its other digits. Correct answer true false false false 357199 7540573 97531000

Answer 1

public class OddDigits {

    public static boolean hasOnlyOddDigits(int n) {
        if (n < 0) {
            n = -n;
        } else if(n == 0) {
            return false;
        }
        while (n > 0) {
            if((n % 10) % 2 == 0) {
                return false;
            }
            n /= 10;
        }
        return true;
    }

    public static void main(String[] args) {
        System.out.println(hasOnlyOddDigits(357199));
        System.out.println(hasOnlyOddDigits(0));
        System.out.println(hasOnlyOddDigits(-7540573));
        System.out.println(hasOnlyOddDigits(97531000));
    }

}

public class OddDigits { public static boolean hasOnlyOddDigits(int n) { if (n < 0) { n = - n: } else if(n = = 0) { return false: } while (n > 0) { if((n % 10) % 2 = = 0) { return false: } n/= 10: } return true: } public static void main(String[] args) { System.out.println(hasOnlyOddDigits(357199)): System.out.println(hasOnlyOddDigits(0)): System.out.println(hasOnlyOddDigits(- 7540573)): System.out.println(hasOnlyOddDigits(97531000)): } } true false false false process finished with exit code 0