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The rate constant of a chemical reaction increased from 0.100 s −1 to 2.70 s −1...

The rate constant of a chemical reaction increased from 0.100 s −1 to 2.70 s −1 upon raising the temperature from 25.0 ∘ C to 43.0 ∘ C . Calculate the value of ( 1 /T 2 − 1 /T 1 ) where T 1 is the initial temperature and T 2 is the final temperature. Then calculate the value of ln(k1/k2) where k1 and k2 correspond to the rate constants at the initial and the final temperatures. What is the activation energy of the reaction? Express your answer numerically in kilojoules per mole.

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