Question

•Pecall thar The polned allele CPO) is completely dom inant to the horned allele po).The following intormation Is avallable: Fomale population : 500 COWS. No genorypio intormanion avai lable. l60% express the honmed phenotgP e Male popuation :20 bulls. Genotypes are as follows: 1o buis are P0/ PO, 2 bulls ae 'heteozygotes, and 8 bulls are pol po a. calculate the qene and genoypic Frequencles in The temale popmation b. calculate fue gene and genorypic frequencies n the male po pulation

Answer 1

Calculate the PO allele using the following equation Female population Total population = 500 Proportion of honed (po) = 60% p + q = 1 p = q-1 p =1- 0.7 p = 0.3 Calculate the 60% of 500 100% 500 60% Calculate the frequency of homozygous PO 60% x 500 = 300 p? = 0.32 = 0.09 100% You have 300 cows with the horned phenotype which means that their genotype must be po po (homozygous for the recessive horned allele) Calculate the frequency of heterozygous 4 2pg = 2 x 0.7 x 0.3 = 0.42 2 Calculate the frequency of the po allele Remember that frequency of homozygous recessive allele is = q? 0.60 frequency of po = 0.7 %3D 3.

Male population Calculate the frequency of each allele 2 Calculate the frequency of each genotype, dividing the number of individuals with each genotype by the total number of population 0.5 = 0.7 Frequency of PO = 10 = 0.5 POPO = 0.4 Frequency of po = 0.6 = 0.1 POpo = 8. = 0.4 popo = 20 20 20