Homework Answers
Heat lost by lead= heat gained by water
=> mlead x clead x (Tf -Ti) = mwater x Cwater x ( Tf - Ti)
=> 34.1 g x 0.160 J/g0C x( 96.9 -27.6)0C = mwater x 4.184 J/g0C x ( 27.6 - 21.1)0C
=> 378.1008 J = mwater x 27.196 J/g
=> mwater =( 378.1008 /27.196) g
=> mwater = 13.9 g = 14 g ( 2 sig. figures)
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