if 0.30 moles of magnesium nitrate reacts with 0.40 moles of sodium phosphate, how many moles of magnesium phosphate are formed?
Balanced chemical equation is:
3 Mg(NO3)2 + 2 Na3PO4 ---> Mg3(PO4)2 + 6 NaNO3
3 mol of Mg(NO3)2 reacts with 2 mol of Na3PO4
for 0.30 mol of Mg(NO3)2, 0.20 mol of Na3PO4 is required
But we have 0.40 mol of Na3PO4
so, Mg(NO3)2 is limiting reagent
we will use Mg(NO3)2 in further calculation
According to balanced equation
mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(NO3)2
= (1/3)*0.30
= 0.10 mol
Answer: 0.10 mol
if 0.30 moles of magnesium nitrate reacts with 0.40 moles of sodium phosphate, how many moles...
10 mL of a 0.30 M sodium phosphate solution reacts with 20 mL of 0.20 M lead(II) nitrate solution What mass of precipitate will form? What is the concentration of nitrate ions left in solution after the reaction is complete? What is the concentration of phosphate ions left in solution after the reaction is complete?
If 1.5484 moles of aluminum nitrate (aq) reacts with excess potassium hydroxide (aq), how many moles of precipitate (solid) will be formed?
2. 20.0 g of aqueous magnesium sulfate reacts with aqueous sodium phosphate and yields a soluble and an insoluble compound. (a) Write and balance the equation and indicate the physical state of reactants and products; (b) calculate the amount of insoluble product assuming more than enough sodium phosphate; and (c) find the number of moles of the insoluble product that can be obtained from 15.0 g sodium phosphate if there is more than enough of MgSO4. (25 points) (a) reaction...
how many moles of potassium nitrate would be produced from 0.50 moles of potassium phosphate
When lead (II) nitrate reacts with sodium iodide, sodium nitrate and lead (II) iodide are formed. Balance the following equation: Pb(NO3)2 (aq) + 2NaI (aq) à PbI2 (s) + 2NaNO3 (aq) What is the limiting reagent in the reaction, If I start with 15.0 grams of lead (II) nitrate and 25.0 grams of sodium iodide, how many grams of sodium nitrate can be formed? How many grams of lead (II) iodide is formed If 6 grams of sodium nitrate...
a. How many grams of sodium phosphate, Na3PO4, are present in 2.23 moles of this compound? grams b. How many moles of sodium phosphate are present in 3.73 grams of this compound? moles a. How many moles of sulfur hexafluoride, SF6, are present in 2.93 grams of this compound? moles b. How many grams of sulfur hexafluoride are present in 3.30 moles of this compound? grams
6.50 mol sodium phosphate completely reacts with magnesium chloride. 2Na3PO4 + 3MgCl2 ----> 6NaCl + Mg3(PO4)2 Show your work in calculating the amount of magnesium chloride that reacts.
silver nitrate + sodium phosphate
+ sodium nitrate yields silver phosphate + sodium phosphate Ib. Silver nitrate Balanced: Complete lonic: Net Ionic: + sodium carbonate yields zine carbonate+ sodium nitrate 2a. Zinc nitrate (ag) (ag) Balanced: Complete lonic: Net lonic: 2b. Zinc nitrate (aq) + sodium phosphate yields zinc phosphate+ sodium nitrate (ag) () (a) Balanced: Complete Ionic: Net Ionic: Report Form - Chemical Reactions 50 yields aluminum iodide (ag) 3a. Aluminum nitrate +potassium iodide (ag) Balanced: Complete lonic: Net...
Question 6 1 pts In the reaction of magnesium chloride with sodium phosphate, how many grams of magnesium phosphate are expected when 50.0 g MgCl2 and 75.0 g Na3PO4 are reacted? 3 MgCl2 (aq) + 2 Na3(PO4)2 + Mg:(PO4)2 (8) + 6 NaCl(aq) How should you solve this problem? Decide which reactant has more grams and use that to calculate the amount of product formed Perform separate and complete stoichiometric evaluation for each reactant. Determine which produces most product and...
1. When mixed, solutions of silver nitrate, AgNO, and sodium phosphate, Na3PO4, will form a precipitate of silver phosphate, Ag2PO4. The balanced equation is: 3AgNO3(aq) + Na3PO4(aq) Ag3PO4(s) + 3NaNO3(aq) Which of the following statements regarding this reaction is incorrect? A. 6 moles of AgNO, will react with 2 moles of Na2PO4 B. 9 moles of AgNO3 will form 2 moles of Ag3PO4, given sufficient Na3PO4 C. 1.5 moles of NaNO, will be formed when 0.5 mole of Na PO,...