Question

A bat hits a ball of 0.145 kg. Initially, the ball travels to the right at 50 m/s, and after being hit it travels to the left at 30 degree respect to the horizontal and a speed of 65 m/s. Find the impulse applied to the ball The average force acting on the ball while it was in contact with the bat for 1.75 ms

Answer 1

According to the given problem,

A) Impluse = Δp = mv₂ - mv₁

x- component :

J_x = 0.145(-65m/s*cos30º - 60m/s) = -16.8623 kg-m/s

y- component:

J_y =  0.145kg * 65m/s * sin30º = 4.7125 kg-m/s

J = 17.5 kg-m/s

B) Force :

F_y = mΔv/Δt = 0.145kg * 65m/s * sin30º / 0.00175s = 2692.857 N
horizontal:
F_x = 0.145kg * (-65m/s*cos30º - 60m/s) / 0.00175s = -9635.588 N

F_avg = 10004.8 N