Question

If short hair (L) is dominant to long hair (I) and black hair (B) is dominant to brown (b) then to determine the genotype of a black short haired animal it should be crossed with c. llBb d. lbb e. Llbb White eyes is an X-linked recessive mutation and yellow body is an autosomal recessive mutation in Drosophila. Starting with a true breeding female mutant only for white eyes mating with a true breeding male mutant only for yellow body, what proportion of the F2 progeny are expected to be males with red eyes and wild type normal body color? b. 1/8 d. 1/4 e. 3/8 A male and female are each heterozygous for both cystic fibrosis (CF) and phenylketonuria (PKU). Both conditions are autosomal recessive and they assort independently. What proportion of the children of this couple will have neither condition? C. 3/8 e. 3/4

Please help me solve these review problems, please show work it'll help me understand how to solve them if on my upcoming exam. Thank you, and I will be sure to give thumbs up.

Answer 1

1. D

Black short hair progeny can have 2 genotypes :-

LLBB

LlBb

To find out the genotype of the progeny, we always cross the progeny with the recessive parent. Here the recessive parent is llbb.

86 ナー 一丈太ちb- LABb aikわ ㄨㄧㄧ-ITA LLBb

On te basis of the phenotype of progeny you get, you can tell the genotype of the given progeny.

2. 3

3. D

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