Homework Answers
a. Ammonia has three dipoles (N-H) which do not cancel out each other, therefore, it is polar.
b. Weak dispersion force (due to 18 electrons) and a strong dipole-dipole force exist in PH3.
c. The hybridisation of N in NH3 is sp3 because one s orbitals and 3 p orbitals involve in formation of hybrid orbitals.
d. According to VSEPR theory , Bond pair =3 and lone pair= 1
PH3 has a trigonal pyramidal geometry.
e. Boiling point of NH3 is higher than PH3 due to existence of hydrogen bonding in NH3 whereas PH3 doesnt under go H-Bonding.
Hence the statement " Normal boiling point of PH3 is higher than NH3 " is incorrect.
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