Question

Three resistors connected in parallel have individual values of 4. 0, 6. 0 and 10. 0 phm, respectively. If this combination is connected in series with a 12-V battery and a 2. 0-ohm resistor, what is the current in the 10-ohm resistor? 0. 59 A 1. 0 A 11 A 16 A

Answer 1

The combined resistance is given as

$R = 2 + \left ( \frac{1}{4}+\frac{1}{6} +\frac{1}{10}\right )^{-1}$

$R = 3.935 \Omega$

Current in the circuit is

$I = \frac{V}{R} = 12/3.935 = 3.05$

The voltage across the parallel combinations is

Current in 10 ohms resistor is

$I_{10} = \frac{5.9 volts}{10} = 0.59 A$