Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g)4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g). Part A If a sample containing 2.50 mL of...

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Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g)4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g). Part A If a sample containing 2.50 mL of...

Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g)4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g).

Part A

If a sample containing 2.50 mL of nitroglycerin (density=1.592g/mL) is detonated, how many total moles of gas are produced?

Express your answer using three significant figures.

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Answer 1

Answer #1

► 1 mass density = Vola volume mass = density X volume L = 1.59 now, determine moles of nitroglyceny moles = mass of C3Hg Nga

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Answer 2

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Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g)4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g). Part A If a sample containing 2.50 mL of...

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Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g Part A If a sample containing 2.50 mL of...

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Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g)4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g). Part A If a sample containing 2.50 mL of...

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Add Answer to: Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g)4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g). Part A If a sample containing 2.50 mL of...

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Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g)4C3H5N3O9(l)→12CO2(g)+6N2(g)+O2(g)+10H2O(g). Part A If a sample containing 2.50 mL of...