Question

Assume that you have 1.10 g of nitroglycerin in a 3000 mL steel container at 20.0°C and 1.00 atm pressure. An explosion occurs, raising the temperature of the container and its contents to 425 °C. The balanced equation is 4 CH: N30,(1) + 12 CO2(g) + 10H2O(g) + 6 N2(g) + O2(9) (Figure 1) Part A How many moles of nitroglycerin were in the container originally? 190 AU O ? TICHNO, = Submit Request Answer Part B How many moles of gas (air) were in the container originally? A m o ai ? niri - mol Submit Request Answer Part How many moles of gas are in the container after the explosion? 19 A26 ? Mais f = fa mol Submit Request Answer Figure < 1 of 1 > Part D What is the pressure (in atmospheres) inside the container after the explosion according to the ideal gas law? IVO ALPm man o ? atm Submit Request Answer Nitroglycerin

Answer 1

Solg wiven that mars of nitroglycerine ( 63 M₂ N30g) = 1. log. A Molen Meus (Ca Hs N30g) = 2278/mol Volisme (Y) = 390m2 2 0.390 Initial Temp. (Ti J= 20°c = 2936 C Pressene (P.) = 1 abr final Temp. (T) = 425°c =6986 4 C2 Mg N3 OG H I 12 02(g) + 10ho (g) + 6N2 lg 1+02(8) ® No. of moles of nitrogle, cine were in the contains onganially (n nito) ... Niito a alven May lolog 6 Кам 74% = 4. fГХ/o ® No of male of gas (air) were in the container originelly Motor = haya lafox 0.3904, Total RTI 0.08206 Lalm x 2931 - molok 0.01623 mol ... Mairan Total nito .0.01623 -0.00485 Main = 0.0038 mo?? © offer Explosion 2 Alread A unale of nitroglycerine give 12 mole of Coz geg 10 mole of hoge 6 mole of New 1 mole of O2(g)

..4.88810* male 9 mihoglycerine give = 0.01456 male of log +0.0122 mole of H2029) + : 0.004 275 molef Mei (9) + 0.00/ 22 mol zez 20103526 mol of air After Exflosion Mais = 0.03526 mel| @ Now, PV La Pevu - Ti Salon x 0.3902 - 293k P2 X 0.39027 698 K > |P2 2 239 walang After explosion final freisen