Question

C++

Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts between1¢ and 99¢. Ask the user how many quarters, dimes, nickels and pennies they need to make that amount. Determine whether the coins specified by the user total the specified amount and give them feedback on their answer including whether they used the minimum or optimum number of coins to produce the amount.

Sample output of a program that satisfies the requirements is shown below. The data entered by the user is in blue.

Sample Output 1: What coins are needed to make $0.39? Quarters? 1 Dimes? 1 Nickels? O Pennies? 4 Excellent that is correct! Sample Output 2: What coins are needed to make $0.48? Quarters? 1 Dimes? 0 Nickels? 4 Pennies? 3 Excellent that is correct! The optimum solution is: Quarters: 1 Dimes: 2 Nickels: 0 Pennies: 3

Answer 1

Answer:

Explanation:

First using rand() function, random number is generated for coins variable, then it is copied to tem for future use as the coins variable will be modified.

Then, asking the user given values for quarters, dimes, nickles and pennies and storing in a, b, c and d.

Then, the actual solution is calculated and stored in quarters, dimes, nickles, and pennies variables.

Then using if else block, the values of user are added and if those coins give a value of temp. Answer is correct. If it does not matches with the optimum solution, optimum solution is printed.

In the else block, it is printed that the answer is wrong and the solution is also printed.

Code:

#include <iostream>
#include <stdlib.h>
using namespace std;

int main()
{
srand(time(0));
  
int coins = rand()%99 + 1;
int temp = coins;
cout<<"What coins are needed to make $0."<<coins<<"?"<<endl<<endl;
int a, b, c, d;
cout<<"Quarters? ";
cin>>a;
cout<<"Dimes? ";
cin>>b;
cout<<"Nickles? ";
cin>>c;
cout<<"Pennies? ";
cin>>d;
  
int quarters = coins/25;
  
coins = coins%25;
  
int dimes = coins/10;
  
coins = coins%10;
  
int nickles = coins/5;

coins = coins%5;
  
int pennies = coins/1;
  

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)
{
cout<<"Excellent that is correct!"<<endl;
  
if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)
{
cout<<"The optimum solution is:"<<endl;
}
}
else
{
cout<<"That is not correct!"<<endl;
cout<<"The solution is: "<<endl;
  
}
  
cout<<"\tQuarters: "<<quarters<<endl;
cout<<"\tDimes: "<<dimes<<endl;
cout<<"\tNickles: "<<nickles<<endl;
cout<<"\tPennies: "<<pennies<<endl;
return 0;
}

Output:

What coins are needed to make $0.85? Quarters? 3 Dimes? O Nickles? 2 Pennies? O Excellent that is correct! The optimum solution is: Quarters: 3 Dimes: 1 Nickles: 0 Pennies: 0 ... Program finished with exit code 0 Press ENTER to exit console. I

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