Question

Problem 1: (20 points) Optimal change You will write a program that uses the // and % operators to figure out how to give change for a specified amount using the minimum number of coins (quarters, dimes, nickels, cents). The good news is that our currency is specifically designed to make this problem easy. For a given number of cents, first use as many quarters as possible, then as many dimes as possible, then as many nickels as possible. Use pennies for what is left over. Assume that the user always enters a positive integer less than 100. Here is a transcript of how your program should work: Enter change:66 Smallest number of coins is 5 Quarters: 2 Dimes: 1 Nickels: 1 Pennies: 1

PLease help!!! how to type them in Python !!!! Python help!! THank you so much

Answer 1

#reading user input

change = int(input("Enter change: "))

#initialising values to coins count

qrt, dime, nickel, penny = 0, 0, 0, 0

#couting quarters

while(change >= 25):

qrt += 1

change -= 25

#couting dimes

while change >= 10:

dime += 1

change -= 10

#couting nickels

while change >= 5:

nickel += 1

change -= 5

#couting pennies

while change > 0:

penny += 1

change -= 1

print("Smallest number of coins is", (qrt+dime+nickel+penny))

print("Quarters:", qrt)

print("Dimes:", dime)

print("Nickels:", nickel)

print("Pennies:", penny)

#reading user input change - int(input("Enter change: ")) #initialising values to coins count qrt, dime, nickel, penny = 0, 0, 0, 0 #couting quarters while(change >= 25): qrt += 1 change -= 25 #couting dimes while change >= 10: dime += 1 change -= 10 #couting nickels while change >= 5: nickel += 1 change -= 5 #couting pennies while change > : penny += 1 change -= 1

#couting pennies while change > 0: penny += 1 change -= 1 print("Smallest number of coins is", (qrt+dime+nickel+penny)) print("Quarters:", qrt) print("Dimes:", dime) print("Nickels:", nickel) print("Pennies:", penny)

Enter change: 84 Smallest number of coins is 8 Quarters: 3 Dimes: 0 Nickels: 1 Pennies: 4