Question

Problem 21.28 Constants A transformer has 400 turns in the primary coil and 200 in the secondary coil.

Answer 1

Given,

N_P=400

N_S=200

PART-B

We know that

$\frac{N_{S}}{N_{P}}=\frac{V_{S}}{V_{P}}$

or,

$\frac{V_{S}}{V_{P}}=\frac{200}{400}=0.5$

PART-C

Since efficiency is 100%, we have

$W_{P}=W_{S}$

where " W_P" and "W_s " are the power of the primary and the secondary coils respectively.

$I_{P}V_{P}=I_{S}V_{S}$

or,

$\frac{I_{S}}{I_{P}}=\frac{V_{P}}{V_{S}}=\frac{1}{0.5}=2$