Question

BiClg according to the equation in Exercise 23 25. What is the mass of mercury that can be prepared from 1.25 of of cobalt metal? Co(s) + HgCl2(aq) → CoC13(aq) + Hg(1)
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Answer #1

Ans 25.

The balanced reaction goes as

2Co + 3HgCl2 = 2CoCl3 + 3Hg

2 moles or 117.87 grams of cobalt makes 3 moles or 601.77 grams of mercury

So 1.25 grams of cobalt will produce ( 1.25 x 601.77) / 117.87

= 6.38 grams of mercury

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