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Note : value of angle B is -45° which may also be written as 180°-45= 135°. Choose whichever you prefer. However as B = tan-1(1/-1) = 135° is best value. As point (a+jb= -1+J1) lies in 2nd quadrant.
You are given vs = A1:72.cos (100t + B1) Vc = A2 · cos (100t + B2) Find vr = Az · cos (100t + B3) with – 180° 5 B3 S 180° + VR . Solve without using a calculator. Given Variables: A1:2V B1:25 degrees A2:2V B2:-20 degrees Determine the following: A3 (V): B3 (degrees):
You are given Vs = A1.12.cos (100t +B) Vc = A2. Cos (100t + B2) Find VR = Az . cos (100t + B3) with - 180° SB3 S 180° + DR w Solve without using a calculator. Given Variables: A1: 8 V B1: 5 degrees A2:8 V B2: -40 degrees Determine the following: A3 (V): B3 (degrees):
Please explain how you added the phasors
together.
You are given vs = A1.v2.cos (100t + B1) Vc = A2 · cos (100t + B2) Find VR = Az · cos (100t + B3) with – 180° 5 B3 = 180° + VC Solve without using a calculator. Given Variables: A1:20 B1: 25 degrees A2:20 B2: -20 degrees Determine the following: A3 (V): B3 (degrees):
vs(t) = A cos(1000t + B1) (a) Find the instantaneous power supplied by the power supply p = A2V3+ A3 cos(2000t + B3) with-180° < B3 S 180 (b) Find the instantaneous power received by the inductor p = A4V3 + A5 cos(2000t + B5) with-180° < B5 < 180 Vs RV3 Given Variables: A1:4V B1:30 degrees R:2 ohm C: 500 uF L:2 mH
vs(t) = A1 cos(1000t + B1) (a) Find the instantaneous power supplied by the power supply p = A2V3+ Az cos(2000t + B3) with –180° < B3 5 180 (b) Find the instantaneous power received by the inductor p = A4V3+ As cos(2000t + B5) with –180º < B5 S 180 vs RV3 = Given Variables: A1:10 V B1: 90 degrees R: 4 ohm C:250 uF L:2mH
please also find a4(W) and b4(VAR) (got cut off in the pic),
thanks!
(t) = A, cos(500+B) Find the complex power S, = +by received by the source Find the complex power S, 4+by received by the resistor Re- Find the complex power S, = s + byl received by the resistors Find the complex power = 14 + he received by the inductor w R Given Variables: A1: 6V B1:45 degrees R1 : 4 ohm R2: 4 ohm L1...
4)
Given Variables:
c : 2 .
Determine the following:
a (.) :
b (.) :
cj CJ Find V1 in cartesian coordinates, i.e., find a and b: Solve without a calculator
Given lines L1 : Ty (1-1)+(21) -2 1 and L2: y 4 8+t2 3 (a) Find the point of intersection of lines Lị and L2. (b) Determine the cosine of the angle between lines L, and L2 at the point of intersection. © Find an equation in form ax +by+cz = d for the plane containing lines L, and Lu. (d) Find the intersection, if any, of the line Ly and the plane P : 3x – 4y + 72...
a)Find the voltage across inductor L1 at t=0^+ (i.e.
just after the switch is opened)
b)Determine the voltage across L1 at time = 5us.
Problem 11: RL Discharging #2 Determine the voltages of a Resistor- Inductor circuit. Switch S1 has been closed for a long time and the Inductor L1 is completely charged. At time t -0s, Switch S1 is opened. R1 S1 R3 R2 L1 Given Variables Name Value Units E1 14 R1 15 kohm R2 kohm R3 17...
You are told that the sources in the two circuits below supply the same average power. (a) Find the average power supplied. (b) Find A1. A v2 cos(500t +B) WWW R Given Variables: V1:9 V R: 3 ohm B1: 30 degrees Determine the following: P (W): A1 (V):