Question

4) Write a shell script to find whether a year was leap year or not. The script will take input from user. The user will enter a year (will only input a valid year) e.g. 1957. The output will be it's a leap year" if it is and "It's not a leap year" if it is not

Answer 1

## code is explained in comments:

#!/bin/bash

echo "Enter Year:" #print this on the terminal

read yr #store in yr variable

yr=$(( $yr % 4 )) #caluclate remainder by dividing by 4

if [ $yr -eq 0 ] #if it is zero ,then print Its a leap year

then

echo "Its is a Leap Year!"

else

echo "Its is not a Leap Year!" #Else print as not a leap year

fi #end of if loop

//output:

//False case :