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The expression 5tan(x)sin(x)+3sec(x) simplifies to Asec(x)−Bcos(x), determine A and B. I'm having trouble applying a trigonometric...

The expression 5tan(x)sin(x)+3sec(x) simplifies to Asec(x)−Bcos(x), determine A and B.

I'm having trouble applying a trigonometric identity to figure out A and B.

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Answer #1

5: Tang.sind + 3secat. = 5 sing. sinx + 3 secal · as sinta + costu = 1 =) sinha=1-costa COST 5 (1-cosa) - + 3secy 5 Sin x + 3

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