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The position of a 0.360 kg object attached to a spring is described by x=(0.270 m)...

The position of a 0.360 kg object attached to a spring is described by x=(0.270 m) cos(0.500pi(t)). (A) Calculate the position at t=0.255 s. (B) Calculate the object's velocity at t=0.255 s.
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Answer #1

2=0.24 Cos (0.571+) @ Put += 0.255 sec X = 0.27 cos [(0.5 )(0.255)] 1* = 0.244 m2 (6) Velocity Na da = -0.27 sin (0.5āt) (0.5

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