Question

A liquid occupies 110 cm³ at a temperature of 12C and 117.64 cm³ at a temperature of 68C.What is coefficient of volumetric expansion for the liquid?

a) 10.21x 10^-4

b) 12.40 x 10 ^-4

c) 6.208 x 10^-4

d) 5.105 x 10^-4

Answer 1

Initial volume of the liquid = V₁ = 110 cm³

Initial temperature of the liquid = T₁ = 12 ^oC

Final volume of the liquid = V₂ = 117.64 cm³

Final temperature of the liquid = T₂ = 68 ^oC

Temperature difference = $\Delta$ T

$\Delta$T = T₂ - T₁

$\Delta$T = 68 - 12

$\Delta$T = 56 ^oC

Coefficient of volumetric expansion for the liquid = $\alpha$

V₂ = V₁(1 + $\alpha$ $\Delta$T)

117.64 = 110(1 + $\alpha$ (56))

1.06945 = 1 + 56$\alpha$

$\alpha$ = 12.40 x 10^-4  oC^-1

Coefficient of volumetric expansion for the liquid = 12.40 x 10^-4oC^-1