2 02 302 12 The KEY l-S moved trompes.mon,A· mo Posir.. on.g' at t-, o FIND...
force reactions
PA Mo-0StNm MO L-15m E- 2.10 MP P=02 Suci 2) FR distablaltdas)) 3 6 HM DeY May
PA Mo-0StNm MO L-15m E- 2.10 MP P=02 Suci 2) FR distablaltdas)) 3 6 HM DeY May
46. Place the following in order of increasing bond length: N2, 02, F2, 12 a. N2 <02<F2 <12 b. N2 <02 <12 <F2 c. 02 <N2 <I2 <F2 d. F2 <02 <N2 <12 e. F2 <N2 <O< 12 47. How many equivalent resonance structures quivalent resonance structures are there for the CO,' ion? a. 1 b. 2 c. 3 d. 4 e. 5 48. Choose the best Lewis structure for SFs anion. -T: 1TT.. -11: :77-9-. .:- : T-00-T TI:...
A) A conducting rod of length L=0.65 m and resistance 2 om is moved with speed v= 15 m/s perpendicular to a magnetic field B= 4.4 x10-3 T. The magnitude of the electric field in the rod is:
- Find L-1{f(t)} f(t) s+2 s-(s + 1)2
Find 1.(t) for t>O in the given circuit. 222 + V 12 1F 7.5e-2 V (+ 4.5u(-1) V 0.5v. + 1110 O [1.0714e-2t – 2.572e-t2cos(1.1181) + 4.791e-#2sin(1.1184] (1) A [-1.0714e-2t – 2.572e-t2cos(1.118t) + 4.791e-2sin(1.1181]u(t) A O [1.0714e-2t – 4.791e-t2cos(1.1186) + 2.572e-t2sin(1.1184]u(t) A O [1.0714e-2t + 2.572e-t2cos(1.1181) – 4.791e-t2sin(1.1189],(0) A
convert to rectangular
(21 =L!o+sin? ") oʻsin o dp do do To T 4 (02 sin?) p2 sin o dp do de 10=0 dp=0 1514)
2) Find the transfer function for the following rotational system (25%) G(s) = 02(*)/T(s) TO I N-m-s/rad fo 1 kg-m? = 25 8.(1) N>= 50 + 0000 4 N-m/rad HHHH
Find the Inverse Transform L {F(s)} of F(s) 38+2 $2 -38 +2 o L 1{F(s)} = 8e2t - 5et OL-'{F(s)} 5 8-1 $ 2 L'{F(s)} = -5e2-8et None of them
302 i(t) Problem 5(20 points) For the circuit on the right: (a) Find the current ift) in the 3-2 resistor in the form i(t) = lalu (b) Calculate the average and rms values of iſt). (c) Calculate the power dissipated in the 3-2 resistor (d) Find the active power of current source 14 V 50cos (2000) 240 mit
can please explain why F(sigma)= u?
We consider the PDE: for given o(t) € H|(12) find the (weak) solution u € H}(2) of V. (g(x)Vu(x)) = 1. The corresponding parameter-to-solution map is defined as F: D(F):= H (1) C H²(2) L’(1) F(o)= u uc H (12) c L’(2) solving b(u, w;o) = f(w) for all w e H7(), b(u, w; 0) := ( D2.Vwdi, f(w):=- / w dr. The associated inverse problem is for u E L(12) find o E...