The resistance of this cone can be found by integration.
Let us consider a thin disk of radius r at a distance x from the right hand. Then from the geometry -
(b-r)/x = (b-a)/h
Solve for radius of disk, r = (a-b)x/h + b
Now, as we know, resistance, R = rho*l/A
Where, l is the length of the conductor and A is the area of cross-section.
The contribution to the resistance from the disk having a thickness dy is
dR = rho*dx/pi*r^2
Now putting the value of r from above and integrating it from o to h
We get -
R = (rho*h)/(pi*a*b)
Putting the values given in the question -
R = (3.9*1.29)/(3.14*0.32*0.69) = 7.26 Ohm
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