

3. (6 pts) Consider a new processor. The memory system is 32-bit byte- addressable. The on-chip...
Memory Hierarchy and Cache Consider a computer with byte-addressable memory. Addresses are 24-bits. The cache is capable of storing a total of 64KB of data, and frames of 32 bytes, Show the format of a 24-bit memory address for: a- Direct mapped cache b- 2-way associative cache c- 4-way associative cache d- For each type of cache above, indicate where would the reference memory address 0DEFB6 map
A byte-addressable memory system contains four memory modules each of which is 32 bits wide by 2^28 cells deep. The system employs a 1 MB 2-way set associative cache with 128-byte cache lines. It also uses a 32-bit CPU-to-memory data bus as well as 32-bit physical addresses. Each memory module requires 4 clock cycles to perform either a read or a write operation. a) Assuming that the memory system is low order interleaved, show the proper 32-bit format for physical...
Problem 6. Suppose we have a computer with 32 megabytes of main memory, 256 bytes of cache, and a block size of 16 bytes. For each configuration below, determine the memory address format, indicating the number of bits needed for each appropriate field (i.e. tag, block, set, offset). Show any relevant calculations. Direct cache mapping and memory is byte-addressable a) Direct cache mapping and memory is word-addressable with a word size of 16 bits b) c) 2-way set associative cache...
Consider a 32 KiB (not KB) cache in a system where the processor uses 64-bit words. The system use the byte address of 36-bits. Each cache line (block) stores 256 bits. a) How many bits are used as the byte offset (b)? How many bits are used as the block offset (m)? b) How many index bits are used? How many blocks (lines) are available in the cache? c) Consider the cache being organized as direct-mapped cache. How many bits...
) Consider an 8-way associative 64 Kilo Byte cache with 32 byte cache lines. Assume memory addresses are 32 bits long. a). Show how a 32-bit address is used to access the cache (show how many bits for Tag, Index and Byte offset). b). Calculate the total number of bits needed for this cache including tag bits, valid bits and data c). Translate the following addresses (in hex) to cache set number, byte number and tag (i) B2FE3053hex (ii) FFFFA04Ehex...
Question 28 7 pts Consider a byte-addressable computer with 24-bit addresses, a cache capable of storing a total of 64K bytes of data, and blocks of 32 bytes. If the computer uses direct mapping, the format of the memory address is as follows: bits for the tag field, bits for the cache block number, and bits for the block offset.
Text:
Explain how a 32-bit byte memory address should be divided into
Tag/Index/Offset fields for each of the cache configurations below.
Note: 1KB = 210 bytes. You must explain how many bits to assign to
each field and the ordering of the three fields. You get at most
50% of the credit if you give the length of each field without an
explanation.
1) A fully associative cache with cache block size = 2 words and
cache size = 512KB....
Set-Associative Cache. Memory is byte addressable. Fill in the missing fields based upon the properties of a set-associative cache. Click on "Select" to access the list of possible answers. Set Block Size Number of Tag Bits Select] Select] Main Memory Size Cache Size 256 B 1) 128 KiB 16 KiB 2) 32 GiB 32 KiB 1 KiB 3) [Select ] 512 KiB 1 KiB [Select ] 10 16 GiB 4 KiB Select ] I Select ] 5) 10 64 MiB...
Consider a virtual memory system with the following properties: 36 bit virtual byte address, 8 KB pages size, and 32 bit physical byte address. Please explain how you determined your answer. a. What is the size of main memory for this system if all addressable frames are used? b. What is the total size of the page table for each process on this processor, assuming that the valid, protection, dirty, and use bits take a total of 4 bits and...
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a 32 blocks direct mapped cache. The cache is initially empty. The following decimal memory addresses are referenced 1020, 1006, 1022, 5106, 994, and 2019 Map the addresses to cache blocks and indicate whether hit or miss. Note: You must use the hexadecimal approach in solving this question. You must also show the computations of dividing the memory address into tag bits, cache index bits,...