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Solve the problem. Round to the nearest tenth unless indicated otherwise. Scores on a test are normally distributed with a me
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Answer #1

Given, mean = \mu = 70 , standard deviation = \sigma = 11.5

We have to find P81, which separates the bottom 81% from top 19%

0.81 0.19 P81 We have to find this value.

Using Excel function ,   =NORMINV( Probability , \mu , \sigma )

P81 = NORMINV( 0.81 , 70, 11.5 ) = 80.09581 \approx 80.1

P81 = 80.1

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