Homework Answers
Plants A and B would have 2 possible genotypes
Dominant traits: D : tall P: smooth
Recessive traits: d: dwarf p: pubescent
a ) DD PP or b) Dd Pp
a) If you consider this genotype , when you crossed it with a dd pp (dwarf- pubescent)
DD PP x dd pp
100% of F1 will have Dd Pp genotype an is not the case
So b) we have to consider this genotype: Dd Pp x dd pp
If the traits are not linkage (non located in the same chromosome)
F1 possible genotypes have to respond as mendelian segregation 1:1:1:1
25% Dd Pp
25% Dd pp
25% dd pp
25% dd Pp
But , this is not the case because for both plants ,the frequencies of F1 doesn´t responds to above proportion. Parental combinations occurs in aprox. 95% and recombinants 3-4% as in our exercise
So :
First conclusion:
Both gene traits are locate in the same chromosome , that means , they are LINKAGE
But in both plants , traits are linkage in a different way because the genotypes frequency of F 1 are quite different
There are 2 types of linkage:
COUPLING : linkage between 2 or more traits either dominant or recessive .In this case:
DP or dp
REPULSION: linkage between 2 or more traits where one is dominant and the other one is recessive
Dp or dP
For plant A DP ( or dp)= 122 plants ( both genotypes have 47% + 48%= 95 % frequency)
dp = 124 plants
We concluded that in A the 2 loci are in coupling configuration ( both linked traits are recessive or dominant each other)
By the other side,
For plant B
Dp = 82 plants ( both genotypes have 48%+48% = 96 % frequency)
dP = 82 plants
In this case B has the loci in repulsion configuration (linked traits are one in recessive form or dominant form and viceversa)
The correct answer is the first one
PLANT A HAS THE TWO LOCI IN COUPLING CONFIGURATION.PLANT B HAS THE TWO LOCI IN REPULSION
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