Question

A particle starts from rest at r->0 =9.0 j^m and moves in the xy-plane with the velocity shown in the figure (Figure 1) . The particle passes through a wire hoop located at r->1 =20 i^m, then continues onward.

At what time does the particle pass through the hoop?

A particle starts from rest at r- > 0 =9.0 j^m and moves in the xy-plane with the velocity shown in the figure (Figure 1) . The particle passes through a wire hoop located at r- > 1 =20 i^m, then continues onward. At what time does the particle pass through the hoop?

Answer 1

We have to view the area below curve, we know that the value of x that the particle move is 20m so:

$A_0_-_>_2=\frac{2*10}{2}=10 m$

$A_0_-_>_2+A_2_-_>_3=10+10=20m$ so the time is $t=3s$

If we had data of vertical velocity we can check the result with the value of vertical distance that is 9 m