Question

Question 3 a) Solve each of the following: i) Convert 111111002 from binary to decimal notation and hexadecimal. (2 marks) i) Add 76B16 +42EA16 hexadecimal numbers. (2 marks) ii) C(8,6) (2 marks) b) There are 20 people who work in an office together. Four of these people are selected to attend four different conferences. The first person selected will go to a conference in Japan, the second will go to Singapore, the third to Thailand, and the fourth to Korea. How many permutations such selections are possible? (2 marks) c) In how many different sequences of combinations can we list 5 novels if there are a total of 9 novels. (2 marks)

Answer 1

Answer for the above questions:

a):

binary to decimal (11111100)₂ = (256)₁₀

binary to hexadecimal (11111100)₂ = (FC)₁₆

= (1&2²) + (1x2°) + (1*2)+ (1x2") + (1x2) Binaay to decimal (1100), +(0x2) + (0x2) -.128 +64 +32 +8+4+0+0. (100)16 = (252)70 Tor Binary to Hexadecimal (1100) (110) (100) 2 FC16. (1100) 1623

2.answer: (76B)₁₆+(42EA)₁₆ = (4A55)₁₆

i Given 768 16+42EA 16 Rough Aalb 16 21 B11 T27 1611 6 COLE S 1 E213 (15)16. z A =10 Ball (=12 d=3 e 14 af =15 42EAR + 76B UA55 20 21

3.answer

C(8,6) = 28

8. т с (6,6) (6!) (8-)! 8x16! 27 61 7 8. 2

b).Answer

P(20,4) = 116280

Answer: P(n,r) = P(20,4) 20! (20 – 4)! = 116280

c.answer:

C(9,5) = 126

C(n,r) = C(9,5) 9! (5!(9 – 5)!) = 126

PS: if you have any doubt mention in the comment section . I will try to solve it as soon as possible