Question

Prelab Part 2 In class, we discussed an op amp comparator circuit as shown below in Figure 4. For this circuit, whenever vi >To make things more interesting, we add some noise to v . The resulting noisy signal is vi(t) = V1 + n(t). Assume that th

a)Which LED will be turned on when vi = 1V? Which LED will be turned on when vi=-1V?

b) Write an equation for v1 as a function of the pot setting ?. Assume ? = 0 corresponds to the slider being all the way up.

c) What do you expect the LEDs to do for a pot setting of ? =  0.4? How about ? =  0.5? How about ? = 0.6?

d) What is the threshold ? for the Schmitt trigger as shown?

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Answer #1

Answer a)

When Vi is 1V, LED1 will glow.

Explanation: Note that Vi is connected to non-inverting input of the op-amp. And inverting input is grounded (i.e. 0V). Therefore the net input to op-amp (V+ - V-) is positive. Therefore Op-amp out will saturate to nearly +5V. Also notice that anode of LED 1 is towards the op-amp output. Therefore LED 1 will get forward-biased in this case and hence this LED will glow.

Similarly when Vi is -1V, the op-amp output will be nearly -5V. Hence LED2 will get forward-biased and hence it will glow

Answer b)

The required equation is

V1 = -10*F + 5

Where F varies from 0 to 1. Zero mean slider is all the way up and 1 means that the slide is all the way down.

Answer c)

Please see the image below for the analysis of the three values of F.

For F = V 0.4 -lox0.4 +5 - In this case vilt varies betweon - v. - Io l you ie. o.auc vcll as V is always positive, theupse L

Answer d) The threshold voltage for the configuration of Schmitt trigger is given by

Vt = ± (R1/R2)*Vs

Here R1 = 20K and R2 = 300K and Vs = 5V

Hence

Vt = ± (20/300)*5 = ±0.33V

Hope this helps


answered by: Abood
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