Question

forces in all members

60 kN Е 30 kN D B A 3 m 3m 3m

Answer 1

otshoun in yuse t us ofsume the Heochon 6OKN A pplying eguohisn of equilibwim EMA O 3 m > 30 x 6 3 VB O С Vв - 60 KN 3m ZV O HA VA t VB 60 KN VA O НА — 30 кN By Method of Toink Conside Node F, Fon ce in EF = O KN F in EC 60KN CCompuessve) Foxce Consid Node A, в0 KN Fouce in Ac = VA Foxce in A B - НА - 30 кN CTerw on A

Conyide Node F, LCFD=45 Resolving foces at F, >30 KN Asuming CF to be in tenvsn, FD 4S 3m с Зm CF Sin45 = 30 KN -. Foжe in CF E H2.H3 кN CF Cos45 = + FD = O FD -30 KN FD = 30KN Ccompuewon surmphon wnarg) > Convdeu Node D, F If thstee mem bey meet in on unloodedl joint of whch aue colinean, then the tiudl C member is а хено ноисе mem ben. Fouce in C D = OKN =7 Fouce in FD - DB DB- 30 AN (compненvе) Convider Node B Let v aume auce in membex CB to be tensile Resolving fouee at B, 6о KN CB Cos5 AB = O

The Overall Forces in the members is as follows:

св 3 30E KN Cos4S wMang Msum phan 42.43 KN C Compuewve ) CB

O member 42.426KN (t 30KN (c) 60kN (c) O member 42.426KN ( 30kN (c) O member 30 kN 30KN (t) 60 kN