Question

Anaerobic water at 20 °C must be transported from one tank to an open container through a pipe with ID = 5.2 cm. Since N2 gas was used to make the water anaerobic, the plant decided to move the water by displacing it with N2 gas under pressure. The closed tank is connected to a gas tank that delivers a constant pressure of 40 psig at the tank gas phase. The exit pipe is 4.6 m above the tank exit and the tank is filled to 3 m above its exit. Calculate the velocity (u in m/s) and volumetric flow rate (Q in m3/s). 40 psig s 4.6 m 3m

Answer 1

By using the Bernoulli's equation we can balance the pressure head at 2 points and can determine the velocity of the flow.

4opsig of copsig 4.6m 3m P1 = 40 psigy 6894076 pa psig 275790 pa. P= atmospheric pressure = 101.325 pa V no cha is large as compared to pipe G. 3m Z- 4.6m So from Bernoullie's equation P + Z1 = 38 ggt + l -29 62 29 at z 275790-10132 ) pa 1000 Kg x 9.81m/82 +(30 3m-4.6m e23 2x9.81 M/82 m3 v₂ = 170 82 m/s D= 0.032m) (14,03), (0.052mx 1.02. 39 Q = 0.038m B

So velocity V=17.82m/s

While the

Flow rate Q=0.038 m³/s

Thanks...

Please Thumbs-up!!