
Try to find out what happens when we press down or up of switch 3? (Please refer to the picture given)
From the given image we can understand that USER_REG is an 8-bit register whose upper 4 bits are the state of four dip switches. We will begin by understanding the condition present in the if statement.
The condition given to the if statement is (USER_REG >> 4) & (0x8). This checks if the bit in position 7 is 1 or 0. It does this as follows:
USER_REG consists of the following bits in the following positions:
7th USER_SW3
6th USER_SW2
5th USER_SW1
4th USER_SW0
3rd USER_LED3
2nd USER_LED2
1st USER_LED1
0th USER_LED0
USER_REG >> 4 shifts the 8-bit number to the right by four positions.
(USER_REG >> 4) is a new number that consists of the following bits (the four new freed up positions are filled up with 0):
7th 0
6th 0
5th 0
4th 0
3rd USER_SW3
2nd USER_SW2
1st USER_SW1
0th USER_SW0
(USER_REG >> 4) & (0x8) checks the 3rd bit position in (USER_REG >> 4) if its 0 or 1. It does this as follows:
(USER_REG >> 4) & (0x8) = (USER_REG >> 4) & (0b00001000) = USER_SW3 & 1
Which is true only when USER_SW3 is 1.
Based on this understanding we can see that when the switch is down (USER_SW3 == 1), the if clause is executed and the input is copied to the output. Similarly, when the switch is up (USER_SW3 == 0), the else clause is executed and the function dsp_process is called.
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Try to find out what happens when we press down or up of switch 3? (Please...
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