A solution prepared by dissolving 513 mg of a sugar (a molecular compound and a nonelectrolyte)...
A solution prepared by dissolving 513 mg of a sugar (a molecular compound and a nonelectrolyte) in 1.00 g of water froze at -2.79 °C. What is the molar mass of this sugar? The value of Kf is 1.86°C/m. Answer in g/mol.
Homework Answers
DTf = i*kf*m
DTf = T0-Tf = 0 - - 2.79 = 2.79 c
DTf = i*Kf*m
i = vanthoff factor of sugar = 1
Kf = frreezing point constant of water = 1.86 K/m
molality(m) = (w/mwt)*(1000/W)
= (0.513/x)*(1000/1)
2.79 = 1*1.86*(0.513/x)*(1000/1)
molarmass of sugar = x = 342 g/mol
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> NICE answer, thank you very much!
Allen Mon, Nov 13, 2023 6:15 PM